Tuesday, October 27, 2015

Hardy-Weinberg

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Population: 1000

Step 1: The given q2 is .853
q2= .853
Step 2: Find the square root of .853 which is .924
q= .924
Step 3: P + Q = 1
p=.077
Step 4: Find the square of .077 which led to .005
p2=.005
Step 5: Multiply 2(.077)(.923)= .14
2pq= .14
Step 6: Multiply q2 , 2pq and p2 by 1000

  •  2pq = .14 x 1000 = 140 

This illustrates the heterozygous individual.


  • q2 = .853 x 1000 = 853

This represents the homozygous recessive.


  • p2 = .005 x 1000 = 5

 This result in the homozygous dominant individual.